在看jpeg解码，里面有对8x8数组进行重排。里面直接提供了unzig表：

int unzig[] = {

0, 1, 8, 16, 9, 2, 3, 10,
17, 24, 32, 25, 18, 11, 4, 5,
12, 19, 26, 33, 40, 48, 41, 34,
27, 20, 13, 6, 7, 14, 21, 28,
35, 42, 49, 56, 57, 50, 43, 36,
29, 22, 15, 23, 30, 37, 44, 51,
58, 59, 52, 45, 38, 31, 39, 46,
53, 60, 61, 54, 47, 55, 62, 63,

};

然后自己写了个产生unzig表的程序。

:-)

代码如下：

复制代码 代码如下:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>

typedef void (*fn)(int, int, int, int, void*);

printpos(int x, int y, int n, int i, void *arr)
{
// printf("%2d%c", x+y*n, i%n==(n-1)?'\n':' ');
int *a;

a = (int*)arr;
printf("%2d%c", a[i], i%n==(n-1)?'\n':' ');
}

unzigasgn(int x, int y, int n, int i, void *arr)
{
int *a;

a = (int*)arr;
a[i] = x+y*n;
}

zigasgn(int x, int y, int n, int i, void *arr)
{
int *a;

a = (int*)arr;
a[x+y*n] = i;
}

zigzag(int n, fn f1, void *arr)
{
int i, x, y;

i = 0;
x = y = 0;
f1(x, y, n, i, arr);
for(;;) {

if(++i >= n*n)
return;
if(x+1 < n){
x++;
f1(x, y, n, i, arr);
}else{
y++;
f1(x, y, n, i, arr);
}

while(x-1 >= 0 && y+1 < n){
x--;
y++;
if(++i >= n*n)
return;
f1(x, y, n, i, arr);
}

if(++i >= n*n)
return;
if(y+1 < n){
y++;
f1(x, y, n, i, arr);
}else{
x++;
f1(x, y, n, i, arr);
}

while(x+1 < n && y-1 >= 0){
x++;
y--;
if(++i >= n*n)
return;
f1(x, y, n, i, arr);
}
}
}

testzigzag(int n)
{
int i;
int n2;
int *arr;

n2 = n*n;
arr = malloc(n*n*sizeof(*arr));

zigzag(n, (fn)zigasgn, arr);
zigzag(n, (fn)printpos, arr);
printf("\n\n");
zigzag(n, (fn)unzigasgn, arr);
zigzag(n, (fn)printpos, arr);
}

main(int argc, char **argv)
{
int n;

n = 8;
if(argc > 1){
n = atoi(argv[1]);
}
testzigzag(n);
return 0;
}

运行结果截图：