一 c读取一行字符串

1 gets

#include <stdio.h> #include <stdlib.h> #include <string.h> int main() { int size = 1024; char* buff = (char*)malloc(size); // read lines while(NULL != gets(buff)){ printf("Read line with len: %d\n", strlen(buff)); printf("%s", buff); } // free buff free(buff); }

利用getchar()读取一个个字符来读取一行

#include <stdio.h> #include <stdlib.h> int my_getline(char* line, int max_size) { int c; int len = 0; while( (c = getchar()) != EOF && len < max_size ){ line[len++] = c; if('\n' == c) break; } line[len] = '\0'; return len; } int main() { int max_size = 1024; char* buff = (char*)malloc( sizeof(char) * max_size ); //getline int len; while(0 != (len = my_getline(buff, max_size))){ printf("Read line with len: %d\n", len); printf("%s", buff); } free(buff); }

二 c++读取一行字符串

cin.get()和cin.getline()#include<iostream>using namespace std;int main(){ cout << "----------getline忽略'\\n-----------------" << endl; char str0[30], str1[30]; cin.getline(str0, 30); cin.getline(str1, 30); cout << "str0:" << str0 << endl; cout << "str1:" << str1 << endl; cout << "---------利用get()消除get()遗留下来的'\\n'-------" << endl; char str2[30], str3[30]; cin.get(str2, 30).get(); // 注意这里！ cin.get(str3, 30).get(); cout << "str1: " << str2 << endl; cout << "str2: " << str3 << endl; cout << "--------没消除get()遗留下来的'\\n'就被下一个get()读取了，所以str5输出为空-----" << endl; char str4[30], str5[30]; cin.get(str4, 30); // 注意这里！ cin.get(str5, 30); cout << "str4: " << str4 << endl; cout << "str5: " << str5 << endl; return 0;}

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