逆时针画圆弧，原理：将360度分割成36份，分别标出每10度角度时的坐标点，然后将每个点连接起来。

#include <iostream> #include <opencv2\core\core.hpp>#include <opencv2\opencv.hpp> #include <opencv2\highgui\highgui.hpp> #include <opencv2\contrib\contrib.hpp> #include <fstream> #include <windows.h> using namespace cv;using namespace std; // 图像、圆心、开始点、结束点、线宽void DrawArc(Mat *src, Point ArcCenter, Point StartPoint, Point EndPoint, int Fill){ if (Fill <= 0) return; vector<Point> Dots; double Angle1 = atan2((StartPoint.y - ArcCenter.y), (StartPoint.x - ArcCenter.x)); double Angle2 = atan2((EndPoint.y - ArcCenter.y), (EndPoint.x - ArcCenter.x)); double Angle = Angle1 - Angle2; Angle = Angle * 180.0 / CV_PI; if (Angle < 0) Angle = 360 + Angle; if (Angle == 0) Angle = 360; int brim = floor(Angle / 10); // 向下取整 Dots.push_back(StartPoint); for (int i = 0; i < brim; i++) { double dSinRot = sin(-(10 * (i + 1)) * CV_PI / 180); double dCosRot = cos(-(10 * (i + 1)) * CV_PI / 180); int x = ArcCenter.x + dCosRot * (StartPoint.x - ArcCenter.x) - dSinRot * (StartPoint.y - ArcCenter.y); int y = ArcCenter.y + dSinRot * (StartPoint.x - ArcCenter.x) + dCosRot * (StartPoint.y - ArcCenter.y); Dots.push_back(Point(x, y)); } Dots.push_back(EndPoint); RNG &rng = theRNG(); Scalar color = Scalar(rng.uniform(100, 255), rng.uniform(100, 255), rng.uniform(100, 255)); for (int i = 0; i < Dots.size() - 1; i++) { line(*src, Dots[i], Dots[i + 1], color, Fill); } Dots.clear();} int main(){ Mat Img = Mat::zeros(800, 800, CV_8UC3); int64 tim = getTickCount(); // 坐标零点 400,400 Point ZeroPoint = Point(400, 400); // 起始坐标 150，-100 Point StartPoint = Point(ZeroPoint.x +150, ZeroPoint.y - (-100)); // 结束坐标 -150，-100 Point EndPoint = Point(ZeroPoint.x - 150, ZeroPoint.y - (-100)); // 圆心相对起始点的坐标 -150,200 int I = StartPoint.x - 150; int J = StartPoint.y - (+200); Point Arc = Point(I, J); // 显示圆心坐标 circle(Img, Arc, 5, Scalar(0, 0, 255), -1); // 显示起始点坐标 circle(Img, StartPoint, 5, Scalar(255, 0, 0), -1); // 显示结束点坐标 circle(Img, EndPoint, 5, Scalar(0, 255, 0), -1); // 图像、圆心、开始点、结束点、线宽 DrawArc(&Img, Arc, StartPoint, EndPoint, 2); imshow("正多边形", Img); tim = getTickCount() - tim; printf("处理耗时: %fms\n\n", tim * 1000 / getTickFrequency()); waitKey(0); return 0;}

效果如下：

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