泛型对象可以实例化吗？

不可以，T t=new T()是不可以的，编译器会报错。由于泛型擦除，编译器在编译时无法确定泛型所对应的真实类型

解决方法

使用反射新建实例

Type superclass = getClass().getGenericSuperclass();ParameterizedType parameterizedType = null;if (superclass instanceof ParameterizedType) { parameterizedType = (ParameterizedType) superclass; Type[] typeArray = parameterizedType.getActualTypeArguments(); if (typeArray != null && typeArray.length > 0) { clazz = (Class<T>) typeArray[0]; }}

执行结果

控制台输出

完整代码

package com.learn.genericinstance;import java.lang.reflect.ParameterizedType;import java.lang.reflect.Type;public class GenericInstanceLearn { public static void main(String[] args) throws InstantiationException, IllegalAccessException { UserDao userDao = new UserDao(); System.out.println(userDao.toString()); }}class Dao<T> { public Class<T> clazz; public T user; public Dao() throws IllegalAccessException, InstantiationException { Type superclass = getClass().getGenericSuperclass(); ParameterizedType parameterizedType = null; if (superclass instanceof ParameterizedType) { parameterizedType = (ParameterizedType) superclass; Type[] typeArray = parameterizedType.getActualTypeArguments(); if (typeArray != null && typeArray.length > 0) { clazz = (Class<T>) typeArray[0]; user= clazz.newInstance(); } } } @Override public String toString() { return "Dao{" + "user=" + user.toString() + '}'; }}class UserDao extends Dao<User> { public UserDao() throws IllegalAccessException, InstantiationException { } @Override public String toString() { return super.toString(); }}class User { String name; public User() { this.name = "default name"; } @Override public String toString() { return "User{" + "name='" + name + '\'' + '}'; }}

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