Java简单的加密解密算法，使用异或运算

实例1：

package cn.std.util;import java.nio.charset.Charset;public class DeEnCode { private static final String key0 = "FECOI()*&<MNCXZPKL"; private static final Charset charset = Charset.forName("UTF-8"); private static byte[] keyBytes = key0.getBytes(charset); public static String encode(String enc){ byte[] b = enc.getBytes(charset); for (int i=0,size=b.length;i<size;i++){ for (byte keyBytes0:keyBytes){ b[i] = (byte) (b[i]^keyBytes0); } } return new String(b); } public static String decode(String dec){ byte[] e = dec.getBytes(charset); byte[] dee = e; for (int i=0,size=e.length;i<size;i++){ for (byte keyBytes0:keyBytes){ e[i] = (byte) (dee[i]^keyBytes0); } } return new String(e); } public static void main(String[] args) { String s="you are right"; String enc = encode(s); String dec = decode(enc); System.out.println(enc); System.out.println(dec); }}

实例2

public static String setEncrypt(String str){ String sn="ziyu"; //密钥 int[] snNum=new int[str.length()]; String result=""; String temp=""; for (int i=0,j=0;i<str.length();i++,j++){ if(j==sn.length()) j=0; snNum[i]=str.charAt(i)^sn.charAt(j); } for (int k=0;k<str.length();k++){ if(snNum[k]<10){ temp="00"+snNum[k]; } else{ if(snNum[k]<100){ temp="0"+snNum[k]; } } result+=temp; } return result;}public static String getEncrypt(String str){ String sn="ziyu"; //密钥 char[] snNum=new char[str.length()/3]; String result=""; for (int i=0,j=0;i<str.length()/3;i++,j++){ if(j==sn.length()) j=0; int n=Integer.parseint(str.substring(i*3,i*3+3)); snNum[i]=(char)((char)n^sn.charAt(j)); } for (int k=0;k<str.length()/3;k++){ result+=snNum[k]; } return result;}}

总结

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