C语言实现洗牌与发牌游戏

时间:2021-05-20

本文实例为大家分享了C语言实现洗牌与发牌游戏的具体代码,供大家参考,具体内容如下

普通版

#include<stdio.h>#include<stdlib.h>#include<time.h>#define SUITS 4#define FACES 13#define CARDS 52void shuffle(int wDeck[][FACES]);void send(int wDeck[][FACES], const char* wSuit[], const char* wFace[]);void main(){ int deck[SUITS][FACES]={0}; const char* suit[SUITS]={"Heart","Diamond","Club","Spade"}; const char* face[FACES]={"Ace","Two","Three","Four","Five","Six","Seven","Eight","Nine","Ten","Jack","Queen","King"}; srand(time(NULL)); shuffle(deck); send(deck, suit, face);}void shuffle(int wDeck[][FACES]){ int row,column,card; for(card=1;card<=CARDS;card++) { row = rand() % SUITS; column = rand() % FACES; while(wDeck[row][column] != 0) { row = rand() % SUITS; column = rand() % FACES; } wDeck[row][column] = card; }}void send(int wDeck[][FACES], const char* wSuit[], const char* wFace[]){ int card,row,column; for(card=1;card<=CARDS;card++) { for(row=0;row<SUITS;row++) { for(column=0;column<FACES;column++) { if(wDeck[row][column] == card) { printf("%5s of %-8s%c",wFace[column],wSuit[row], card % 2 ==0 ? '\n' : '\t'); } } } }}

高性能版

//先按顺序填满52个格子,再产生随机格子相互交换#include<stdio.h>#include<stdlib.h>#include<time.h>#define CARDS 52#define FACES 13struct card{ const char* face; const char* suit;};typedef struct card Card;void shuffle(Card *const wDeck);void send(const Card *const wDeck);//指针常量与数据常量均不可以改变,都用const限定,*前是限定指针,*后是限定数据void main(){ const char* wSuit[]={"Heart","Diamond","Club","Spade"};//指针数组是一个数组 const char* wFace[]={"Ace","Two","Three","Four","Five","Six","Seven","Eight","Nine","Ten","Jack","Queen","King"}; int i; Card deck[CARDS]; for(i=0;i<CARDS;i++) { deck[i].suit = wSuit[i / FACES]; deck[i].face = wFace[i % FACES]; } srand(time(NULL)); shuffle(deck); send(deck);}void shuffle(Card *const wDeck){ int i,j; Card temp; for(i=0;i<CARDS;i++) { j = rand() % CARDS; temp = wDeck[i]; wDeck[i] = wDeck[j]; wDeck[j] = temp; }}void send(const Card *const wDeck){ int i; for(i=0;i<CARDS;i++) { printf("%5s of %-8s%c",wDeck[i].face,wDeck[i].suit, (i+1) % 4 == 0 ? '\n' : '\t'); }}

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持。

声明:本页内容来源网络,仅供用户参考;我单位不保证亦不表示资料全面及准确无误,也不保证亦不表示这些资料为最新信息,如因任何原因,本网内容或者用户因倚赖本网内容造成任何损失或损害,我单位将不会负任何法律责任。如涉及版权问题,请提交至online#300.cn邮箱联系删除。

相关文章