C语言实现简单万年历

时间:2021-05-20

本文实例为大家分享了C语言实现简单万年历的具体代码,供大家参考,具体内容如下

#include <stdio.h>#include<stdlib.h>int year, month;int run[12] = { 31,29,31,30,31,30,31,31,30,31,30,31 };int ping[12] = { 31,28,31,30,31,30,31,31,30,31,30,31 };char week[7][10] = { "SUN","MON","TUE","WED","THU","FRI","SAT" }; bool IsLeap(int year){ if (year % 400 == 0 || (year % 4 == 0 && year % 100 != 0)) //判断闰年 { return true; } else { return false; }}void PrintStar(){ printf("\t\t\t万年历\t\t\t\n"); printf("****************************************************\n"); for (int i = 0; i < 7; i++) { printf("%s\t", week[i]); } printf("\n");}int DaySum(int year, int month){ int sum = 0; for (int i = 1990; i < year; i++) { if (IsLeap(i)) { sum += 366; } else { sum += 365; } } for (int i = 0; i < month - 1; i++) { if (IsLeap(year)) { sum += run[i]; } else { sum += ping[i]; } } return sum;} void PrintCal(int sum, int year, int month){ int nRes, nTmp; nRes = sum % 7+1;//前面空几格 nTmp = 7 - nRes;//从第几格开始打印 for (int i = 0; i < nRes; i++) { printf("\t"); } if (IsLeap(year)) { for (int i = 1; i < run[month - 1]+1; i++) { printf("%d\t", i); if (nTmp == i || (i - nTmp) % 7 == 0) { printf("\n"); } } printf("\n"); } else { for (int i = 1; i < ping[month - 1]+1; i++) { printf("%d\t", i); if (nTmp == i || (i - nTmp) % 7 == 0) { printf("\n"); } } printf("\n"); } }int main(void){ while (1) { scanf_s("%d %d", &year, &month); PrintStar(); PrintCal(DaySum(year, month), year, month); printf("****************************************************\n"); } return 0; }

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