C语言数据结构之双向循环链表的实例

时间:2021-05-20

数据结构之双向循环链表

实例代码:

#include <stdlib.h>#include <stdio.h>#include <malloc.h>typedef struct Node{ struct Node *pNext; int data; struct Node *prior;} NODE,*PNODE;PNODE CreatList();void TreNode(PNODE pHead);bool isEmpty(PNODE pHead);int getCount(PNODE pHead);bool insertNode (PNODE pHead,int pos,int val);bool detNode (PNODE pHead,int pos,int *pVal);void sort(PNODE pHead);int main(){ int val; PNODE pHead = NULL; pHead = CreatList(); TreNode(pHead); printf("链表不为空!\n"); printf("链表不为空!\n"); if(insertNode(pHead, 4, 7)) printf("插入成功!插入的元素为:%d\n", 7); else printf("插入失败!\n"); //重新遍历链表 TreNode(pHead); //删除元素测试 if(detNode(pHead, 3, &val)) printf("元素删除成功!删除的元素是:%d\n", val); else printf("元素删除失败!\n"); TreNode(pHead); return 0 ;}PNODE CreatList(){ int i ; int val; int length; PNODE pHead = (PNODE)malloc(sizeof(NODE)); if(NULL==pHead) { printf("创建链表失败!\n"); exit(-1); } pHead->pNext = NULL; pHead->prior = NULL; PNODE pTail = pHead; printf("请输入您想要创建链表结点的个数:len = "); scanf("%d", &length); for(i = 0;i < length;i++){ printf("请输入第%d个结点的值:", i+1); scanf("%d", &val); PNODE pnew = (PNODE)malloc(sizeof(NODE)); if(NULL==pHead) { printf("创建链表失败!\n"); exit(-1); } pnew->data = val; // pTail->pNext = pnew; pTail->pNext = pnew; pnew->prior = pTail; pnew->pNext = pHead; pHead->prior = pnew; pTail = pnew; } return pHead; }void TreNode(PNODE pHead){ PNODE p = pHead->pNext; while(p!= pHead ){ printf("%d",p->data); p = p->pNext; } printf("\n"); return ; }bool isEmpty(PNODE pHead){ if(NULL==pHead->pNext) return true; else return false;}int getCount(PNODE pHead){ int i =0 ; PNODE p = pHead->pNext; while(NULL != p){ p = p->pNext; i++; } return i ;}bool insertNode (PNODE pHead,int pos,int val){ int i = 0;// PNODE p = pHead;PNODE p =pHead; while(NULL !=p && i<pos-1){ p = p->pNext; i++; } if(NULL == p || i>pos-1) { return false; } scanf("%d", &val); PNODE pNew = (PNODE)malloc(sizeof(NODE)); if(NULL==pNew) { printf("创建链表失败!\n"); exit(-1); } pNew ->data = val; PNODE q = p->pNext; p->pNext = pNew; pNew->prior = p; pNew->pNext = q; return true;}bool detNode (PNODE pHead,int pos,int *pVal){ int i = 0;// PNODE p = pHead;PNODE p = pHead; while(NULL !=p && i<pos-1){ p = p->pNext; i++; } if(NULL == p || i>pos-1) { return false; } *pVal = p->pNext->data; PNODE q = p->pNext; p->pNext = p->pNext->pNext; free(q); q = NULL; return true;}void sort(PNODE pHead){ int i,j,k,t; k = getCount(pHead); PNODE p,q; for(i = 0,p=pHead->pNext;i < k-1;i++,p = p->pNext) { for(j = i+1,q = p->pNext;j<k;j++,q = q->pNext){ if(p->data > q->data ){ t = p->data; p->data = q->data; q->data = t; } } } }

实现效果:

感谢阅读,希望能帮助到大家,谢谢大家对本站的支持!

声明:本页内容来源网络,仅供用户参考;我单位不保证亦不表示资料全面及准确无误,也不保证亦不表示这些资料为最新信息,如因任何原因,本网内容或者用户因倚赖本网内容造成任何损失或损害,我单位将不会负任何法律责任。如涉及版权问题,请提交至online#300.cn邮箱联系删除。

相关文章