C语言实现520表白代码 祝你表白成功!

时间:2021-05-20

本文实例为大家分享了C语言实现520表白的具体代码,供大家参考,具体内容如下

在这个狂虐单身狗的节日,实在无聊写了几行也不知道向谁告白的代码,献丑献丑:

#include<stdio.h>#include<math.h>int main(){ float y, x, z; printf("那一天\n"); printf("第一次遇见你\n"); printf("忘不了\n"); printf("你的容颜\n"); printf("若轻云之蔽月,如流风之回雪\n"); printf("\n\n\n"); printf("其实\n"); printf("有一句话\n"); printf("我一直想对你说:\n"); for (double y = 2.5; y >= -1.6; y = y - 0.2) { for (double x = -3; x <= 4.8; x = x + 0.1) { (pow((x*x + y*y - 1), 3) <= 3.6*x*x*y*y*y || (x>-2.4 && x<-2.1 && y<1.5 && y>-1) || (((x<2.5 && x>2.2) || (x>3.4 && x<3.7)) && y>-1 && y<1.5) || (y>-1 && y<-0.6 && x<3.7 && x>2.2)) ? printf("*") : printf(" "); } printf("\n"); } getchar();}

运行效果图:


代码二

#include <stdio.h>#include <math.h>#include <stdlib.h>#define I 20#define R 340#include <string.h>int main(){ char answer[10]; printf("遇到你\n我才发现\n曾经所有的条件\n似乎都成了我等你的借口\n\n"); printf("请允许我,从今往后映入你\n明媚的眼\n"); printf("输入yes或no,点击Enter"); printf("\n "); scanf("%s", answer); char b[4]="yes"; if(strcmp(answer,b)==0) { float y, x, z, f; for (y = 1.5f; y > -1.5f; y -= 0.1f) { for (x = -1.5f; x < 1.5f; x += 0.05f) { z = x * x + y * y - 1; f = z * z*z - x * x*y*y*y; putchar(f <= 0.0f ? "*********"[(int)(f*-8.0f)] : ' '); } putchar('\n'); } long time; for (;;) { system("color a"); for (time = 0; time<99999999; time++); system("color b"); for (time = 0; time<99999999; time++); system("color c"); for (time = 0; time<99999999; time++); system("color d"); for (time = 0; time<99999999; time++); system("color e"); for (time = 0; time<99999999; time++); system("color f"); for (time = 0; time<99999999; time++); system("color 0"); for (time = 0; time<99999999; time++); system("color 1"); for (time = 0; time<99999999; time++); system("color 2"); for (time = 0; time<99999999; time++); system("color 3"); for (time = 0; time<99999999; time++); system("color 4"); for (time = 0; time<99999999; time++); system("color 5"); for (time = 0; time<99999999; time++); system("color 6"); for (time = 0; time<99999999; time++); system("color 7"); for (time = 0; time<99999999; time++); system("color 8"); for (time = 0; time<99999999; time++); system("color 9"); } getchar(); } else { printf("\n好吧,那就相忘于江湖吧!\n"); } return 0;}

以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持。

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