这是一个用C++写的五子棋的小程序，关于A若是占据了已经下了的位置处理的不好。改动 hight，与width ，与q[][] 可以将棋盘扩大。

#include<iostream>#include<vector>using namespace std;class qipan{public: qipan() {} ~qipan() {}; //向上下左右，斜的方向 char left(int x, int y) {//检查是否合适 if (x >= 1 && x <= hight&& y - 1 >= 1 && y - 1 <= width) { return q[x][y - 1]; } else { return 'F'; } } char right(int x, int y) { if (x >= 1 && x <= hight&&y + 1 >= 1 && y + 1 <= width) { return q[x][y + 1]; } else { return 'F'; } } char up(int x, int y) { if (x - 1 >= 1 && x - 1 <= hight && y >= 1 && y <= width) { return q[x - 1][y]; } else { return 'F'; } } char down(int x, int y) { if (x + 1 >= 1 && x + 1 <= hight && y >= 1 && y <= width) { return q[x + 1][y]; } else { return 'F'; } } char left_up(int x, int y) { if (x - 1 >= 1 && x - 1 <= hight && y - 1 >= 1 && y - 1 <= width) { return q[x - 1][y - 1]; } else { return 'F'; } } char left_down(int x, int y) { if (x + 1 >= 1 && x + 1 <= hight && y - 1 >= 1 && y - 1 <= width) { return q[x + 1][y - 1]; } else { return 'F'; } } char right_up(int x, int y) { if (x - 1 >= 1 && x - 1 <= hight && y + 1 >= 1 && y + 1 <= width) { return q[x - 1][y + 1]; } else { return 'F'; } } char right_down(int x, int y) { if (x + 1 >= 1 && x + 1 <= hight && y + 1 >= 1 && y + 1 <= width) { return q[x + 1][y + 1]; } else { return 'F'; } } void init_cur() { h_cur = hang; l_cur = lie; } bool win() { bool WIN = false; char temp = q[hang][lie]; //以上为例，每次先看上面的5个，假如一样，iter++；否则 break；再加上下的方向，同样iter++；最后iter+1==5,WIN=true;并且退出 //各个方向重复，上下左右，斜着的。 //赢了直接退出。 //显示是谁赢了 //左右 int count_lr = 1; init_cur(); for (int i = 0; i < 4; i++) { if (left(h_cur, l_cur) == temp) count_lr++; else break; l_cur--; } init_cur(); for (int i = 0; i < 4; i++) { if (right(h_cur, l_cur) == temp) count_lr++; else break; l_cur++; } if (count_lr == 5) WIN = true; //上下 int count_ud = 1; init_cur(); for (int i = 0; i < 4; i++) { if (up(h_cur, l_cur) == temp) count_ud++; else break; h_cur--; } init_cur(); for (int i = 0; i < 4; i++) { if (down(h_cur, l_cur) == temp) count_ud++; else break; h_cur++; } if (count_ud == 5) WIN = true; //左斜 int count_lt = 1; init_cur(); for (int i = 0; i < 4; i++) { if (left_up(h_cur, l_cur) == temp) count_lt++; else break; h_cur--; l_cur--; } init_cur(); for (int i = 0; i < 4; i++) { if (left_down(h_cur, l_cur) == temp) count_lt++; else break; h_cur++; l_cur--; } if (count_lt == 5) WIN = true; //右边斜 int count_rt = 1; init_cur(); for (int i = 0; i < 4; i++) { if (right_up(h_cur, l_cur) == temp) count_rt++; else break; h_cur--; l_cur++; } init_cur(); for (int i = 0; i < 4; i++) { if (right_down(h_cur, l_cur) == temp) count_rt++; else break; h_cur++; l_cur++; } if (count_rt == 5) WIN = true; return WIN; } void qipan_array() { for (int i = 0; i < hight; i++) { for (int j = 0; j < width; j++) q[i][j] = '+'; } } void prin_qipan() { //打印二维数组；每一行要打印上行号，以及列号 for (int i = 0; i <hight; i++) { for (int j = 0; j < width; j++) { cout << q[i][j] << " "; } cout << i; cout << endl; } for (int j = 0; j <width; j++) { cout << j << " "; } cout << endl << "________________________________" << endl; } int xiaqi(int player) { if (player == 1) { q[hang][lie] = '*'; } else if (player == 2) { q[hang][lie] = '@'; } else cout << "input player is wrong" << endl; return 0; } //初始化行列 int gethang(int h) { hang = h; return 0; } int getlie(int l) { lie = l; return 0; } int h_cur; int l_cur; const int hight = 9; const int width = 9; int hang; int lie; char q[9][9];};int main(){ int hang, lie; qipan wzq; wzq.qipan_array(); cout << "A 与B 玩五子棋" << endl; cout << "A use * and B use @" << endl; cout << "________________________________" << endl; for (int i = 0; i < 15; i++) { cout << "A 输入行： "; cin >> hang; cout << "A 输入列： "; cin >> lie; if (wzq.q[hang][lie] != '+') cout << "输入的行列数字已经有人占据了" << endl; else { wzq.gethang(hang); wzq.getlie(lie); wzq.xiaqi(1); wzq.prin_qipan(); if (wzq.win()) { cout << "A is winner" << endl; exit(0); } } //b 开始了 cout << "B 输入行： "; cin >> hang; cout << "B 输入列： "; cin >> lie; if (wzq.q[hang][lie] != '+') cout << "输入的行列数字已经有人占据了" << endl; else { wzq.gethang(hang); wzq.getlie(lie); wzq.xiaqi(2); wzq.prin_qipan(); if (wzq.win()) { cout << "B is winner" << endl; exit(0); } } } return 0;}

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