方法一：递归算法

/// <summary>/// 一列数的规则如下: 1、1、2、3、5、8、13、21、34求第30位数是多少， 用递归算法实现。(C#语言)/// </summary>/// <param name="pos"></param>/// <returns></returns>public int GetNumberAtPos(int pos){ if(pos==0||pos==1) { return 1; } int res = GetNumberAtPos(pos - 1) + GetNumberAtPos(pos - 2); return res;}

方法二：不用递归

using System;using System.Collections;using System.Collections.Generic;using System.Text;namespace Test{ public class Class1 { private ArrayList list = new ArrayList(); public Class1() { } public Class1(int num) : base() { int i; for (i = 1; i <= num; i++) { list.Add(Calculation(i)); } } private int Calculation(int num) { if (num == 1 || num == 2) return 1; else return Convert.ToInt32(list[num - 2]) + Convert.ToInt32(list[num - 3]); } public int Calculation() { return Convert.ToInt32(list[list.Count - 1]); } } public class test { public static void Main() { int j; int num; for (j = 1; j < 100; j++) { Console.WriteLine("你要计算第多少位:"); string readstr; readstr = Console.ReadLine(); if (!string.IsNullOrEmpty(readstr)) { if (int.TryParse(readstr, out num)) { if (num < 1) continue; else { Class1 c1 = new Class1(num); Console.WriteLine(c1.Calculation()); } } else { continue; } } else { break; } } } }}

方法三：用循环实现

public long getNumber(int pos){ long one = 1; long two = 1; if (pos == 0 || pos == 1) { return 1; } int i = 3; long sum = 1; while (i <= pos) { sum = one + two; one = two; two = sum; i++; } return sum;}

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