本文实例讲述了C#图像边缘检测（Roberts）的方法。分享给大家供大家参考。具体如下：

//定义roberts算子函数private static Bitmap robert(Bitmap a){ int w = a.Width; int h = a.Height; try { Bitmap dstBitmap = new Bitmap(w, h, System.Drawing.Imaging.PixelFormat.Format24bppRgb); System.Drawing.Imaging.BitmapData srcData = a.LockBits(new Rectangle (0, 0, w, h), System.Drawing.Imaging.ImageLockMode.ReadOnly, System.Drawing.Imaging.PixelFormat.Format24bppRgb); System.Drawing.Imaging.BitmapData dstData = dstBitmap.LockBits(new Rectangle (0, 0, w, h), System.Drawing.Imaging.ImageLockMode.WriteOnly, System.Drawing.Imaging.PixelFormat.Format24bppRgb); unsafe { byte* pIn = (byte*)srcData.Scan0.ToPointer(); byte* pOut = (byte*)dstData.Scan0.ToPointer(); byte* p; int stride = srcData.Stride; for (int y = 0; y < h; y++) { for (int x = 0; x < w; x++) { //边缘八个点像素不变 if (x == 0 || x == w - 1 || y == 0 || y == h - 1) { pOut[0] = pIn[0]; pOut[1] = pIn[1]; pOut[2] = pIn[2]; } else { int r0, r5, r6, r7; int g5, g6, g7, g0; int b5, b6, b7, b0; double vR, vG, vB; //右 p = pIn + 3; r5 = p[2]; g5 = p[1]; b5 = p[0]; //左下 p = pIn + stride - 3; r6 = p[2]; g6 = p[1]; b6 = p[0]; //正下 p = pIn + stride; r7 = p[2]; g7 = p[1]; b7 = p[0]; //中心点 p = pIn; r0 = p[2]; g0 = p[1]; b0 = p[0]; vR = (double)(Math .Abs (r0-r5)+Math .Abs ( r5-r7)); vG = (double)(Math.Abs(g0 - g5) + Math.Abs(g5 - g7)); vB = (double)(Math.Abs(b0 - b5) + Math.Abs(b5 - b7)); if (vR > 0) { vR = Math.Min(255, vR); } else { vR = Math.Max(0, vR); } if (vG > 0) { vG = Math.Min(255, vG); } else { vG = Math.Max(0, vG); } if (vB > 0) { vB = Math.Min(255, vB); } else { vB = Math.Max(0, vB); } pOut[0] = (byte)vB; pOut[1] = (byte)vG; pOut[2] = (byte)vR; } pIn += 3; pOut += 3; } pIn += srcData.Stride - w * 3; pOut += srcData.Stride - w * 3; } } a.UnlockBits(srcData); dstBitmap.UnlockBits(dstData); return dstBitmap; } catch { return null; }}

希望本文所述对大家的C#程序设计有所帮助。