C#实现农历日历的方法

时间:2021-05-20

本文实例讲述了C#实现农历日历的方法。分享给大家供大家参考。

具体实现方法如下:

复制代码 代码如下://天干
private static string []TianGan = {"甲","乙","丙","丁","戊","己","庚","辛","壬","癸"};
//地支
private static string []DiZhi = {"子","丑","寅","卯","辰","巳","午","未","申","酉","戌","亥"};
//十二生肖
private static string []ShengXiao = {"鼠","牛","虎","兔","龙","蛇","马","羊","猴","鸡","狗","猪"};
//农历日期
private static string []DayName = {"*","初一","初二","初三","初四","初五","初六","初七","初八","初九","初十", "十一","十二","十三","十四","十五", "十六","十七","十八","十九","二十", "廿一","廿二","廿三","廿四","廿五", "廿六","廿七","廿八","廿九","三十"};
//农历月份
private static string []MonthName = {"*","正","二","三","四","五","六","七","八","九","十","十一","腊"};
//公历月计数天
private static int []MonthAdd = {0,31,59,90,120,151,181,212,243,273,304,334};
//农历数据
private static int []LunarData = {2635,333387,1701,1748,267701,694,2391,133423,1175,396438 ,3402,3749,331177,1453,694,201326,2350,465197,3221,3402 ,400202,2901,1386,267611,605,2349,137515,2709,464533,1738 ,2901,330421,1242,2651,199255,1323,529706,3733,1706,398762 ,2741,1206,267438,2647,1318,204070,3477,461653,1386,2413 ,330077,1197,2637,268877,3365,531109,2900,2922,398042,2395 ,1179,267415,2635,661067,1701,1748,398772,2742,2391,330031 ,1175,1611,200010,3749,527717,1452,2742,332397,2350,3222 ,268949,3402,3493,133973,1386,464219,605,2349,334123,2709 ,2890,267946,2773,592565,1210,2651,395863,1323,2707,265877};
/// <summary>
/// 获取对应日期的农历
///
/// </summary>
/// <param name="dtDay">公历日期</param>
///
///<returns></returns>
public string GetLunarCalendar(DateTime dtDay)
{
string sYear = dtDay.Year.ToString(); string sMonth = dtDay.Month.ToString();
string sDay = dtDay.Day.ToString();
int year;
int month;
int day;
try {
year = int.Parse(sYear);
month = int.Parse(sMonth);
day = int.Parse(sDay);
}
catch {
year = DateTime.Now.Year;
month = DateTime.Now.Month;
day = DateTime.Now.Day;
}
int nTheDate;
int nIsEnd;
int k, m, n, nBit, i;
string calendar = string.Empty;
//计算到初始时间1921年2月8日的天数:1921-2-8(正月初一)
nTheDate = (year - 1921) * 365 + (year - 1921) / 4 + day + MonthAdd[month - 1] - 38;
if ((year % 4 == 0) && (month > 2)) nTheDate += 1;
//计算天干,地支,月,日
nIsEnd = 0; m = 0; k = 0; n = 0;
while (nIsEnd != 1)
{
if (LunarData[m] < 4095) k = 11; else k = 12; n = k; while (n >= 0)
{ //获取LunarData[m]的第n个二进制位的值
nBit = LunarData[m];
for (i = 1; i < n + 1; i++) nBit = nBit / 2;
nBit = nBit % 2;
if (nTheDate <= (29 + nBit)) { nIsEnd = 1; break; }
nTheDate = nTheDate - 29 - nBit; n = n - 1;
}
if (nIsEnd == 1) break; m = m + 1;
}
year = 1921 + m; month = k - n + 1; day = nTheDate;

#region 格式化日期显示为三月廿四
if (k == 12)
{
if (month == LunarData[m] / 65536 + 1)
month = 1 - month;
else if (month > LunarData[m] / 65536 + 1)
month = month - 1;
}
//生肖//
calendar = ShengXiao[(year - 4) % 60 % 12].ToString() + "年 ";
// // //天干// //
calendar += TianGan[(year - 4) % 60 % 10].ToString();
// // //地支// //
calendar += DiZhi[(year - 4) % 60 % 12].ToString() + " ";
//// //农历月//
if (month < 1)
//
calendar += "闰" + MonthName[-1 * month].ToString() + "月";
else
calendar += MonthName[month].ToString() + "月";
//// //农历日//
calendar += DayName[day].ToString() + "日";////
return calendar;////
#endregion
}

希望本文所述对大家的C#程序设计有所帮助。

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