在PyQt中没有直接提供左键双击的判断方法，需要自己实现，其思路主要如下所示：

1、起动一个定时器，判断在指定的时间之内，点击次数超过2次，则视为双击（其主要思路判断两次点击的时间差在预测的条件以内）

2、 起动一个定时器，判断在指定的时间之内，点击次数超过2次，另外再获取鼠标点击的坐标，如果前后两次点击的坐标位置，属于同一个位置，满足这两个条件则判断为双击（其主要思路判断两次点击的时间差在预测的条件以内，且点击的坐标在预设的坐标之内，允许存在一定的偏差）

from PyQt5.QtCore import QTimerfrom PyQt5 import QtCore, QtGui, QtWidgetsclass myWidgets(QtWidgets.QTableWidget): def __init__(self, parent=None): super(myWidgets, self).__init__(parent) self.isDoubleClick = False self.mouse = "" def mousePressEvent(self, e): # 左键按下 if e.buttons() == QtCore.Qt.LeftButton: QTimer.singleShot(0, lambda: self.judgeClick(e)) # 右键按下 elif e.buttons() == QtCore.Qt.RightButton: self.mouse = "右" # 中键按下 elif e.buttons() == QtCore.Qt.MidButton: self.mouse = '中' # 左右键同时按下 elif e.buttons() == QtCore.Qt.LeftButton | QtCore.Qt.RightButton: self.mouse = '左右' # 左中键同时按下 elif e.buttons() == QtCore.Qt.LeftButton | QtCore.Qt.MidButton: self.mouse = '左中' # 右中键同时按下 elif e.buttons() == QtCore.Qt.MidButton | QtCore.Qt.RightButton: self.mouse = '右中' # 左中右键同时按下 elif e.buttons() == QtCore.Qt.LeftButton | QtCore.Qt.MidButton | QtCore.Qt.RightButton: self.mouse = '左中右' def mouseDoubleClickEvent(self,e): # 双击 self.mouse = "双击" self.isDoubleClick=True def judgeClick(self,e): if self.isDoubleClick== False: self.mouse="左" else: self.isDoubleClick=False self.mouse = "双击"

或

from PyQt5.QtCore import QTimerfrom PyQt5 import QtCore, QtGui, QtWidgetsclass myWidgets(QtWidgets.QTableWidget): def __init__(self, parent=None): super(myWidgets, self).__init__(parent) self.mouse = "" self.timer=QTimer(self) self.timer.timeout.connect(self.singleClicked) def singleClicked(self): if self.timer.isActive(): self.timer.stop() self.mouse="左" def mouseDoubleClickEvent(self,e): if self.timer.isActive() and e.buttons() ==QtCore.Qt.LeftButton: self.timer.stop() self.mouse="双击" super(myWidgets,self).mouseDoubleClickEvent(e) def mousePressEvent(self,e): if e.buttons()== QtCore.Qt.LeftButton: self.timer.start(1000) elif e.buttons()== QtCore.Qt.RightButton: self.mouse="右" super(myWidgets,self).mousePressEvent(e)

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