循环链表就是将单链表的末尾指向其头部，形成一个环。循环链表的增删操作和单链表的增删操作
区别不大。只是增加时，需要考虑空链表增加第一个节点的特殊情况；删除时需考虑删除节点是头/尾节点，和链表中只有一个节点的特殊情况。

golang实现：

type Node struct { value int next *Node}type Circle struct { tail *Node lenth int}// 增加节点：func (c *Circle) add(value int) { newNode := &Node{value, nil} if c.lenth == 0 { //空链表中添加节点 c.tail = newNode c.tail.next = newNode } else { newNode.next = c.tail.next c.tail.next = newNode c.tail = newNode } c.lenth += 1 c.printCircle()}// 删除节点：func (c *Circle) remove(v int) { if c.lenth == 0 { fmt.Println("空环") return } else if c.lenth == 1 && c.tail.value == v { //链表中只有一个节点的特殊情况 c.tail = nil c.lenth = 0 c.printCircle() return } pre := c.tail cur := c.tail.next // 头节点 for i := 0; i < c.lenth; i++ { if cur.value == v { if cur == c.tail { //如果删除的节点是尾节点,需更新tail c.tail = pre } pre.next = cur.next c.lenth -= 1 c.printCircle() return } pre = cur cur = cur.next } fmt.Println(v, "不在环中")}//打印节点：func (c *Circle) printCircle() { if c.lenth == 0 { fmt.Println("空环") return } cur := c.tail.next // 头节点 for i := 0; i < c.lenth; i++ { fmt.Printf("%d ", cur.value) cur = cur.next } fmt.Println()}func testCircle() { var circle *Circle = new(Circle) //for i := 1; i <=41; i++ { // circle.add(i) //} circle.add(1) circle.remove(10) circle.printCircle()}

python实现：

class Node: def __init__(self, value, next=None): self.value = value self.next = next def __str__(self): return str(self.value)class Circle: def __init__(self): self.tail = None self.lenth = 0 # 增加节点 def add(self, v): new_node = Node(v) if self.lenth == 0: # 空链表中添加节点 self.tail = new_node self.tail.next = new_node else: new_node.next = self.tail.next self.tail.next = new_node self.tail = new_node self.lenth += 1 # 删除节点 def remove(self, v): if self.lenth == 0: print("空环") return elif self.lenth == 1 and self.tail.value == v: # 链表中只有一个节点的特殊情况 self.tail = None self.lenth = 0 return pre = self.tail cur = self.tail.next # 头节点 for i in range(self.lenth): if cur.value == v: if cur == self.tail: # 如果删除的节点是尾节点，需更新tail self.tail = pre pre.next = cur.next self.lenth -= 1 return pre = cur cur = cur.next print(v, "不在环中") # 打印链表 def print_circle(self): if self.lenth == 0: print('空环') return cur = self.tail.next # 头节点 for i in range(self.lenth): print(cur, end=" ") cur = cur.next print()def test(): c = Circle() for i in range(10): c.add(i) c.print_circle() c.remove(0) c.print_circle() c.remove(10) c.print_circle() c.remove(9) c.print_circle() c.remove(4) c.print_circle()

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