前些天有位网友建议我在博客中添加RSS订阅功能，觉得挺好，所以自己抽空看了一下如何在Django中添加RSS功能，发现使用Django中的syndication feed framework很容易实现。

具体实现步骤和代码如下：

1、Feed类

# -*- coding: utf-8 -*-from django.conf import settingsfrom django.contrib.syndication.views import Feedfrom django.utils.feedgenerator import Rss201rev2Feed from blog.models import Articlefrom .constants import SYNC_STATUS class ExtendedRSSFeed(Rss201rev2Feed): mime_type = 'application/xml' """ Create a type of RSS feed that has content:encoded elements. """ def root_attributes(self): attrs = super(ExtendedRSSFeed, self).root_attributes() attrs['xmlns:content'] = 'http://purl.org/rss/1.0/modules/content/' return attrs def add_item_elements(self, handler, item): super(ExtendedRSSFeed, self).add_item_elements(handler, item) handler.addQuickElement(u'content:encoded', item['content_encoded']) class LatestArticleFeed(Feed): feed_type = ExtendedRSSFeed title = settings.WEBSITE_NAME link = settings.WEBSITE_URL author = settings.WEBSITE_NAME description = settings.WEBSITE_DESC + u"关注python、django、vim、linux、web开发和互联网" def items(self): return Article.objects.filter(hided=False, published=True, sync_status=SYNC_STATUS.SYNCED).order_by('-publish_date')[:10] def item_extra_kwargs(self, item): return {'content_encoded': self.item_content_encoded(item)} def item_title(self, item): return item.title # item_link is only needed if NewsItem has no get_absolute_url method. def item_link(self, item): return '/article/%s/' % item.slug def item_description(self, item): return item.description def item_author_name(self, item): return item.creator.get_full_name() def item_pubdate(self, item): return item.publish_date def item_content_encoded(self, item): return item.content

2、URL配置

from django import VERSION if VERSION[0: 2] > (1, 3): from django.conf.urls import patterns, include, urlelse: from django.conf.urls.defaults import patterns, include, urlfrom .feeds import LatestArticleFeed urlpatterns = patterns( '', url(r'^feed/$', LatestArticleFeed()),)