如果点击按钮，运行了一个比较耗时的操作，那么界面会卡死。

import tkinter as tkimport time def onclick(text, i): time.sleep(3) text.insert(tk.END, '按了第{}个按钮\n'.format(i)) root = tk.Tk() text = tk.Text(root)text.pack() tk.Button(root, text='按钮1', command=lambda :onclick(text,1)).pack()tk.Button(root, text='按钮2', command=lambda :onclick(text,2)).pack() root.mainloop()

解决办法：

方式一、直接开线程

import tkinter as tkimport timeimport threading songs = ['爱情买卖','朋友','回家过年','好日子']movies = ['阿凡达','猩球崛起'] def music(songs): global text # 故意的，注意与movie的区别 for s in songs: text.insert(tk.END, "听歌曲：%s \t-- %s\n" %(s, time.ctime())) time.sleep(3) def movie(movies, text): for m in movies: text.insert(tk.END, "看电影：%s \t-- %s\n" %(m, time.ctime())) time.sleep(5) def thread_it(func, *args): '''将函数打包进线程''' # 创建 t = threading.Thread(target=func, args=args) # 守护 !!! t.setDaemon(True) # 启动 t.start() # 阻塞--卡死界面！ # t.join() root = tk.Tk() text = tk.Text(root)text.pack() tk.Button(root, text='音乐', command=lambda :thread_it(music, songs)).pack()tk.Button(root, text='电影', command=lambda :thread_it(movie, movies, text)).pack() root.mainloop()

方式二、继承 threading.Thread 类

import tkinter as tkimport timeimport threading songs = ['爱情买卖','朋友','回家过年','好日子']movies = ['阿凡达','猩球崛起'] def music(songs): global text # 故意的，注意与movie的区别 for s in songs: text.insert(tk.END, "听歌曲：%s \t-- %s\n" %(s, time.ctime())) time.sleep(3) def movie(movies, text): for m in movies: text.insert(tk.END, "看电影：%s \t-- %s\n" %(m, time.ctime())) time.sleep(5) class MyThread(threading.Thread): def __init__(self, func, *args): super().__init__() self.func = func self.args = args self.setDaemon(True) self.start() # 在这里开始 def run(self): self.func(*self.args) root = tk.Tk() text = tk.Text(root)text.pack() tk.Button(root, text='音乐', command=lambda :MyThread(music, songs)).pack()tk.Button(root, text='电影', command=lambda :MyThread(movie, movies, text)).pack() root.mainloop()

三、或者，搞一个界面类：

import tkinter as tkimport timeimport threading songs = ['爱情买卖','朋友','回家过年','好日子'] films = ['阿凡达','猩球崛起'] class Application(tk.Tk):def __init__(self): super().__init__() self.createUI() # 生成界面 def createUI(self): self.text = tk.Text(self) self.text.pack() tk.Button(self, text='音乐', command=lambda :self.thread_it(self.music, songs)).pack(expand=True, side=tk.RIGHT) # 注意lambda语句的作用！ tk.Button(self, text='电影', command=lambda :self.thread_it(self.movie, films)).pack(expand=True, side=tk.LEFT) # 逻辑：听音乐 def music(self, songs): for x in songs: self.text.insert(tk.END, "听歌曲：%s \t-- %s\n" %(x, time.ctime())) print("听歌曲：%s \t-- %s" %(x, time.ctime())) time.sleep(3) # 逻辑：看电影 def movie(self, films): for x in films: self.text.insert(tk.END, "看电影：%s \t-- %s\n" %(x, time.ctime())) print("看电影：%s \t-- %s" %(x, time.ctime())) time.sleep(5) # 打包进线程（耗时的操作） @staticmethod def thread_it(func, *args): t = threading.Thread(target=func, args=args) t.setDaemon(True) # 守护--就算主界面关闭，线程也会留守后台运行（不对!） t.start() # 启动 # t.join() # 阻塞--会卡死界面！ app = Application()app.mainloop()

以上这篇解决python tkinter界面卡死的问题就是小编分享给大家的全部内容了，希望能给大家一个参考，也希望大家多多支持。