本文实例为大家分享了python3射线法判断点是否在多边形内的具体代码，供大家参考，具体内容如下

#!/usr/bin/python3.4# -*- coding:utf-8 -*- def isPointinPolygon(point, rangelist): #[[0,0],[1,1],[0,1],[0,0]] [1,0.8] # 判断是否在外包矩形内，如果不在，直接返回false lnglist = [] latlist = [] for i in range(len(rangelist)-1): lnglist.append(rangelist[i][0]) latlist.append(rangelist[i][1]) print(lnglist, latlist) maxlng = max(lnglist) minlng = min(lnglist) maxlat = max(latlist) minlat = min(latlist) print(maxlng, minlng, maxlat, minlat) if (point[0] > maxlng or point[0] < minlng or point[1] > maxlat or point[1] < minlat): return False count = 0 point1 = rangelist[0] for i in range(1, len(rangelist)): point2 = rangelist[i] # 点与多边形顶点重合 if (point[0] == point1[0] and point[1] == point1[1]) or (point[0] == point2[0] and point[1] == point2[1]): print("在顶点上") return False # 判断线段两端点是否在射线两侧 不在肯定不相交 射线（-∞，lat）（lng,lat） if (point1[1] < point[1] and point2[1] >= point[1]) or (point1[1] >= point[1] and point2[1] < point[1]): # 求线段与射线交点 再和lat比较 point12lng = point2[0] - (point2[1] - point[1]) * (point2[0] - point1[0])/(point2[1] - point1[1]) print(point12lng) # 点在多边形边上 if (point12lng == point[0]): print("点在多边形边上") return False if (point12lng < point[0]): count +=1 point1 = point2 print(count) if count%2 == 0: return False else: return True if __name__ == '__main__': print(isPointinPolygon([0.8,0.8], [[0,0],[1,1],[0,1],[0,0]]))

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