本文实例讲述了Python实现的序列化和反序列化二叉树算法。分享给大家供大家参考，具体如下：

题目描述

请实现两个函数，分别用来序列化和反序列化二叉树

序列化二叉树

先序遍历二叉树

def recursionSerialize(self, root): series = '' if root == None: series += ',$' else: series += (',' + str(root.val)) series += self.recursionSerialize(root.left) series += self.recursionSerialize(root.right) return series def Serialize(self, root): return self.recursionSerialize(root)[1:]

结果：

root = TreeNode(11)root.left = TreeNode(2)root.right = TreeNode(3)series = Solution().Serialize(root)print(series)>>>11,2,$,$,3,$,$

反序列化

先构建根节点，然后左节点，右节点，同样是递归

注意由于使用的是字符串的表示形式，可以先转化为list，

print(series.split(','))>>>['11', '2', '$', '$', '3', '$', '$']

然后再处理就不需要将大于10的数字转换过来了：

def getValue(self, s, sIndex): #处理超过10的数字，将数字字符转变为数字 val = 0 while ord(s[sIndex]) <= ord('9') and ord(s[sIndex]) >= ord('0'): val = val * 10 + int(s[sIndex]) sIndex += 1 return val, sIndex - 1

下面是反序列化的递归函数：

def Deserialize(self, s): if self.sIndex < len(s): if s[self.sIndex] == ',': self.sIndex += 1 if s[self.sIndex] == '$': return None val, self.sIndex = self.getValue(s, self.sIndex) treeNode = TreeNode(val) self.sIndex += 1 treeNode.left = self.Deserialize(s) self.sIndex += 1 treeNode.right = self.Deserialize(s) return treeNode

完整解法

class TreeNode: def __init__(self, x): self.val = x self.left = None self.right = Noneclass Solution: def __init__(self): self.sIndex = 0 def recursionSerialize(self, root): series = '' if root == None: series += ',$' else: series += (',' + str(root.val)) series += self.recursionSerialize(root.left) series += self.recursionSerialize(root.right) return series def Serialize(self, root): return self.recursionSerialize(root)[1:] def getValue(self, s, sIndex): #处理超过10的数字，将数字字符转变为数字 val = 0 while ord(s[sIndex]) <= ord('9') and ord(s[sIndex]) >= ord('0'): val = val * 10 + int(s[sIndex]) sIndex += 1 return val, sIndex - 1 def Deserialize(self, s): if self.sIndex < len(s): if s[self.sIndex] == ',': self.sIndex += 1 if s[self.sIndex] == '$': return None val, self.sIndex = self.getValue(s, self.sIndex) treeNode = TreeNode(val) self.sIndex += 1 treeNode.left = self.Deserialize(s) self.sIndex += 1 treeNode.right = self.Deserialize(s) return treeNode

更多关于Python相关内容感兴趣的读者可查看本站专题：《Python数据结构与算法教程》、《Python加密解密算法与技巧总结》、《Python编码操作技巧总结》、《Python函数使用技巧总结》、《Python字符串操作技巧汇总》及《Python入门与进阶经典教程》

希望本文所述对大家Python程序设计有所帮助。