麻烦的

# TODO 构造增广矩阵，假设A，b行数相同def augmentMatrix(A, b): if(len(A) != len(b)): raise 'The number of rows is different' result = [] for i in range(len(A)): row = [] for j in range(len(A[i])): row.append(A[i][j]) for j in range(len(b[i])): row.append(b[i][j]) result.append(row) return result

优化后

# TODO 构造增广矩阵，假设A，b行数相同def augmentMatrix(A, b): return [AA + bb for AA, bb in zip(A,b)] A = [[1,2,3],[4,5,6],[7,8,9]]b = [[1],[2],[3]]print augmentMatrix(A,b)[[1, 2, 3, 1], [4, 5, 6, 2], [7, 8, 9, 3]]

注：解读一下AA+bb, 在 python中, [1, 2, 3] + [4]这样的表达式会返回[1, 2, 3, 4]

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