SQL> SELECT KTUXEUSN, KTUXESLT, KTUXESQN, 2 KTUXESTA Status, KTUXECFL Flags ,KTUXESIZ 3 FROM x$ktuxe 4 WHERE ktuxesta!='INACTIVE'; KTUXEUSN KTUXESLT KTUXESQN STATUS FLAGS KTUXESIZ ---------- ---------- ---------- ---------------- ------------------------ ---------- 13 5 47447 ACTIVE DEAD 2819919 39 0 502 ACTIVE NONE 1 43 45 480 ACTIVE NONE 0SQL> / KTUXEUSN KTUXESLT KTUXESQN STATUS FLAGS KTUXESIZ ---------- ---------- ---------- ---------------- ------------------------ ---------- 13 5 47447 ACTIVE DEAD 2819919<----该值没减小。 39 0 502 ACTIVE NONE 1 43 45 480 ACTIVE NONE 0

查询v$px_session和v$fast_start_servers,显示很多并行进程在rollback，根据以往的工程经验：

于是改为

SQL>alter system set fast_start_parallel_rollback=false scope=both;

之后，再次运行

SQL> SELECT KTUXEUSN, KTUXESLT, KTUXESQN, 2 KTUXESTA Status, KTUXECFL Flags ,KTUXESIZ 3 FROM x$ktuxe 4 WHERE ktuxesta!='INACTIVE'; KTUXEUSN KTUXESLT KTUXESQN STATUS FLAGS KTUXESIZ ---------- ---------- -------------------------- ------------------------ ---------- 13 5 47447 ACTIVE DEAD 2033516 35 29 502 ACTIVE NONE 1 SQL> / KTUXEUSN KTUXESLT KTUXESQN STATUS FLAGS KTUXESIZ ---------- ---------- -------------------------- ------------------------ ---------- 13 5 47447 ACTIVE DEAD 2033433<---该值不断变小。 35 29 502 ACTIVE NONE 1

使用如下脚本查看回滚完毕的预计时间（以天为单位）：

SQL> set serveroutput on SQL> declare 2 l_start number; 3 l_end number; 4 begin 5 select ktuxesiz into l_startfrom x$ktuxe where KTUXEUSN=13 and KTUXESLT=5; 6 dbms_lock.sleep(60); 7 select ktuxesiz into l_endfrom x$ktuxe where KTUXEUSN=13 and KTUXESLT=5; 8 dbms_output.put_line('time estDay:'|| round(l_end/(l_start -l_end)/60/24,2)); 9 end; 10 / time est Day:.21

24*0.21=5.04小时。即：预计5.04小时后回滚完毕。

另外注意：在其他环境使用时，请注意替换KTUXEUSN=13和KTUXESLT=5