Mysql将查询结果集转换为JSON数据 前言学生表学生成绩表查询单个学生各科成绩（转换为对象JSON串并用逗号拼接）将单个学生各科成绩转换为数组JSON串将数组串作为value并设置key两张表联合查询(最终SQL，每个学生各科成绩)最终结果

前言

我们经常会有这样一种需求，一对关联关系表，一对多的关系，使用一条sql语句查询两张表的所有记录，例：一张学生表，一张学生各科成绩表，我们想要用一条SQL查询出每个学生各科成绩；

学生表

CREATE TABLE IF NOT EXISTS `student`( `id` INT UNSIGNED AUTO_INCREMENT, `name` VARCHAR(100) NOT NULL PRIMARY KEY ( `id` ))ENGINE=InnoDB DEFAULT CHARSET=utf8;INSERT INTO student( id, name ) VALUES ( 1, '张三' );INSERT INTO student( id, name ) VALUES ( 2, '李四' );

学生成绩表

CREATE TABLE IF NOT EXISTS `score`( `id` INT UNSIGNED AUTO_INCREMENT, `name` VARCHAR(100) NOT NULL `student_id` INT(100) NOT NULL, `score` VARCHAR(100) NOT NULL PRIMARY KEY ( `id` ))ENGINE=InnoDB DEFAULT CHARSET=utf8;INSERT INTO score( id, name, student_id, score) VALUES ( 1, '数学', 1, '95.5' );INSERT INTO score( id, name, student_id, score) VALUES ( 2, '语文', 1, '99.5' );INSERT INTO score( id, name, student_id, score) VALUES ( 3, '数学', 2, '95.5' );INSERT INTO score( id, name, student_id, score) VALUES ( 4, '语文', 2, '88' );

查询单个学生各科成绩（转换为对象JSON串并用逗号拼接）

SELECT GROUP_CONCAT(JSON_OBJECT( 'id',id,'name',name,'student_id',student_id, 'score', score)) as scores FROM scroe where student_id = 1;## 查询结果## {"id": 1, "name": "数学", "student_id": 1, "score": "95.5"},{"id": 2, "name": "语文", "student_id": 1, "score": "99.5"}

将单个学生各科成绩转换为数组JSON串

SELECT CONCAT('[', GROUP_CONCAT(JSON_OBJECT( 'id',id,'name',name,'student_id',student_id, 'score', score)), ']') as scores FROM scroe where student_id = 1## 查询结果## [{"id": 1, "name": "数学", "student_id": 1, "score": "95.5"},{"id": 2, "name": "语文", "student_id": 1, "score": "99.5"}]

将数组串作为value并设置key

SELECT CONCAT('{"scoreData":[', GROUP_CONCAT(JSON_OBJECT( 'id',id,'name',name,'student_id',student_id, 'score', score)), ']}') as scores FROM scroe where student_id = 1## 查询结果## {"scoreData": [{"id": 1, "name": "数学", "student_id": 1, "score": "95.5"},{"id": 2, "name": "语文", "student_id": 1, "score": "99.5"}]}

两张表联合查询(最终SQL，每个学生各科成绩)

SELECT id, name,(SELECT CONCAT('[', GROUP_CONCAT(JSON_OBJECT( 'id',id,'name',name,'student_id',student_id, 'score', score)), ']') as scores FROM scroe WHERE student_id = stu.id) AS scoresfrom student stu## [{"id": 1, "name": "数学", "student_id": 1, "score": "95.5"},{"id": 2, "name": "语文", "student_id": 1, "score": "99.5"}]

最终结果

ID NAME SCORES 1 张三 [{“id”: 1, “name”: “数学”, “student_id”: 1, “score”: “95.5”},{“id”: 2, “name”: “语文”, “student_id”: 1, “score”: “99.5”}] 2 李四 [{“id”: 3, “name”: “数学”, “student_id”: 1, “score”: “95.5”},{“id”:4, “name”: “语文”, “student_id”: 1, “score”: “88”}]

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