代码如下所示：

SELECT @i:=@i+1 rowNum,if(@total=t.s_score,@rank,@rank:=@i) rank,@total:=t.s_score,t.*from(select t1.* ,t2.s_score from student t1 LEFT JOIN score t2 on t1.s_id=t2.s_id and t2.c_id="01" ORDER BY t2.s_score desc)t,(select @i:=0,@rank:=0,@total:=null) s ;SELECT @i:=@i+1 rowNum,if(@total=t.s_score,@rank,@rank:=@rank+1) rank,@total:=t.s_score,t.*from(select t1.* ,t2.s_score from student t1 LEFT JOIN score t2 on t1.s_id=t2.s_id and t2.c_id="01" ORDER BY t2.s_score desc)t,(select @i:=0,@rank:=0,@total:=null) s ;

Mysql 获取成绩排序后的名次

其实就是输出mysql的排序后的行号

RT：获取单个用户的成绩在所有用户成绩中的排名

可以分两步：

1、查出所有用户和他们的成绩排名

select id,maxScore,(@rowNum:=@rowNum+1) as rowNo from t_user, (select (@rowNum :=0) ) b order by t_user.maxScore desc

2、查出某个用户在所有用户成绩中的排名

select u.rowNo from ( select id,(@rowNum:=@rowNum+1) as rowNo from t_user, (select (@rowNum :=0) ) b order by t_user.maxScore desc ) u where u.id="2015091810371700001";

总结

以上所述是小编给大家介绍的Mysql排序获取排名，希望对大家有所帮助，如果大家有任何疑问请给我留言，小编会及时回复大家的。在此也非常感谢大家对网站的支持！