本文实例讲述了PHP正则验证Email的方法。分享给大家供大家参考。具体如下：

<?phpfunction validateEmail($email){ $isValid = true; $atIndex = strrpos($email, "@"); if (is_bool($atIndex) && !$atIndex) { $isValid = false; } else { $domain = substr($email, $atIndex+1); $local = substr($email, 0, $atIndex); $localLen = strlen($local); $domainLen = strlen($domain); if ($localLen < 1 || $localLen > 64) { // local part length exceeded $isValid = false; } else if ($domainLen < 1 || $domainLen > 255) { // domain part length exceeded $isValid = false; } else if ($local[0] == '.' || $local[$localLen-1] == '.') { // local part starts or ends with '.' $isValid = false; } else if (preg_match('/\\.\\./', $local)) { // local part has two consecutive dots $isValid = false; } else if (!preg_match('/^[A-Za-z0-9\\-\\.]+$/', $domain)) { // character not valid in domain part $isValid = false; } else if (preg_match('/\\.\\./', $domain)) { // domain part has two consecutive dots $isValid = false; } else if(!preg_match('/^(\\\\.|[A-Za-z0-9!#%&`_=\\/$\'*+?^{}|~.-])+$/', str_replace("\\\\","",$local))) { // character not valid in local part unless // local part is quoted if (!preg_match('/^"(\\\\"|[^"])+"$/', str_replace("\\\\","",$local))) { $isValid = false; } } if ($isValid && !(checkdnsrr($domain,"MX") || checkdnsrr($domain,"A"))) { // domain not found in DNS $isValid = false; } } return $isValid;}?>

PS：这里再为大家提供2款非常方便的正则表达式工具供大家参考使用：

JavaScript正则表达式在线测试工具：
http://tools.jb51.net/regex/javascript

正则表达式在线生成工具：
http://tools.jb51.net/regex/create_reg

希望本文所述对大家的php程序设计有所帮助。