php解析字符串里所有URL地址的方法

时间:2021-05-26

本文实例讲述了php解析字符串里所有URL地址的方法。分享给大家供大家参考。具体如下:

<?php// $html = the html on the page// $current_url = the full url that the html came from//(only needed for $repath)// $repath = converts ../ and / and // urls to full valid urlsfunction pageLinks($html, $current_url = "", $repath = false){ preg_match_all("/\<a.+?href=(\"|')(?!javascript:|#)(.+?)(\"|')/i", $html, $matches); $links = array(); if(isset($matches[2])){ $links = $matches[2]; } if($repath && count($links) > 0 && strlen($current_url) > 0){ $pathi = pathinfo($current_url); $dir = $pathi["dirname"]; $base = parse_url($current_url); $split_path = explode("/", $dir); $url = ""; foreach($links as $k => $link){ if(preg_match("/^\.\./", $link)){ $total = substr_count($link, "../"); for($i = 0; $i < $total; $i++){ array_pop($split_path); } $url = implode("/", $split_path) . "/" . str_replace("../", "", $link); }elseif(preg_match("/^\/\//", $link)){ $url = $base["scheme"] . ":" . $link; }elseif(preg_match("/^\/|^.\//", $link)){ $url = $base["scheme"] . "://" . $base["host"] . $link; }elseif(preg_match("/^[a-zA-Z0-9]/", $link)){ if(preg_match("/^http/", $link)){ $url = $link; }else{ $url = $dir . "/" . $link; } } $links[$k] = $url; } } return $links;}header("content-type: text/plain");$url = "https://www.jb51.net";$html = file_get_contents($url);// Gets links from the page:print_r(pageLinks($html));// Gets links from the page and formats them to a full valid url:print_r(pageLinks($html, $url, true));

希望本文所述对大家的php程序设计有所帮助。

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