最近接了一个项目，其中有一需求是用php获取一年有几周以及每周开始日期和接触日期。在网上找些资料没有合适的，于是自己做了一份，下面通过两种方式实现PHP获取一年有几周以及每周开始日期和结束日期

代码一：

<?phpheader("Content-type:text/html;charset=utf-8");date_default_timezone_set("Asia/Shanghai");$year = (int)$_GET['year'];$week = (int)$_GET['week'];$weeks = date("W", mktime(0, 0, 0, 12, 28, $year));echo $year . '年一共有' . $weeks . '周<br />';if ($week > $weeks || $week <= 0){ $week = 1;}if ($week < 10){ $week = '0' . $week;}$timestamp['start'] = strtotime($year . 'W' . $week);$timestamp['end'] = strtotime('+1 week -1 day', $timestamp['start']);echo $year . '年第' . $week . '周开始时间戳：' . $timestamp['start'] . '<br />';echo $year . '年第' . $week . '周结束时间戳：' . $timestamp['end'] . '<br />';echo $year . '年第' . $week . '周开始日期：' . date("Y-m-d", $timestamp['start']) . '<br />';echo $year . '年第' . $week . '周结束日期：' . date("Y-m-d", $timestamp['end']);?>

代码二：

<?phpheader("Content-type:text/html;charset=utf-8");function getIsoWeeksInYear($year){ $date = new DateTime; $date->setISODate($year, 53); return ($date->format("W") === "53" ? 53 : 52);}function weekday($custom_date){ $week_start = date('d-m-Y', strtotime('this week monday', $custom_date)); $week_end = date('d-m-Y', strtotime('this week sunday', $custom_date)); $week_array[0] = $week_start; $week_array[1] = $week_end; return $week_array;}echo '<br> Weeks in 2013<br>' . getIsoWeeksInYear(2013);$weekday = weekday(strtotime(date('d-m-Y', strtotime('5-8-2013'))));echo '<br> 10-8-2013';echo '<br>Start: ' . $weekday[0];echo '<br>End: ' . $weekday[1];?>

以上本文的全部内容，希望对大家学习PHP获取一年有几周以及每周开始日期和结束日期，有所帮助。