引子

排序在编程中随处可见，从开始学习变成，到项目开发，基本上或多或少会遇到一些排序问题，接下来我要写的是我在实际开发终于到的一个排序问题，一开始卡了我很久，后面随着知识积累，实践变多才解决掉了，不知道是不是我搜索关键字不对，还是其他原因，百度也没有找到这方面的内容。

数据结构和需求

var arr = [ {"soNumber" : "52085848","item" : "313281","amount" : "3"}, {"soNumber" : "52085846","item" : "313321","amount" : "10"}, {"soNumber" : "52085848","item" : "313330","amount" : "5"}, {"soNumber" : "52085846","item" : "313321","amount" : "4"}, {"soNumber" : "52085843","item" : "313338","amount" : "13"}, {"soNumber" : "52085843","item" : "422784","amount" : "108"} ]

数据结构如上，数组结构，每个数组元素由对象构成，soNumber代表采购订单编号，item代表物料，现需求是soNumber（采购订单编号）从小到大排序，且基于相同的采购订单下的物料数据编号需要从小到大排列。

两层排序实现代码

解决思路：

先将soNumber按从小到大的顺序整理成数组，然后以销售订单数组为外层循环，实际数据为内层循环，引入一个中间数组，中间数组中的item从小到大排序，最后按顺序将所有的中间数组元素放入新数组中。

实现代码：

/** * 两层排序算法 */ function multilayerSorting() { var arr = [ { "soNumber" : "52085848", "item" : "313281", "amount" : "3" }, { "soNumber" : "52085846", "item" : "313321", "amount" : "10" }, { "soNumber" : "52085848", "item" : "313330", "amount" : "5" }, { "soNumber" : "52085846", "item" : "313321", "amount" : "4" }, { "soNumber" : "52085843", "item" : "313338", "amount" : "13" }, { "soNumber" : "52085843", "item" : "422784", "amount" : "108" } ] // 整理soNumber成数组,并且从小到大排列 var soData = getSoData(arr); var newData = []; for ( var i in soData) { var midData = [] for ( var j in arr) { if (soData[i] == arr[j].soNumber) { midData.push(arr[j]); } } midData = midData.sort(function(obj1, obj2) { var val1 = Number(obj1.item); var val2 = Number(obj2.item); if (val1 < val2) { return -1; } else if (val1 > val2) { return 1; } else { return 0; } }); log.debug('midData', midData); for ( var m in midData) { newData.push(midData[m]); } } log.debug('newData', newData); return newData; } function getSoData(arr) { var soData = []; for ( var i in arr) { if (soData.indexOf(arr[i].soNumber) == -1) { soData.push(arr[i].soNumber); } } soData.sort(); log.debug('soData', soData); return soData; }<br>

最终数组截图:

对比一开始的数组和排序后的数组确实实现了按照soNumber和item两个部分顺序排列,但是也可以看到圈出来的部分的amount金额在相同的soNumber和item下并没有顺序,如果要实现amount部也有序呢?

三层排序

实现代码:

/** * 三层排序算法 */ function multilayerSorting() { var arr = [ { "soNumber" : "52085848", "item" : "313281", "amount" : "3" }, { "soNumber" : "52085846", "item" : "313321", "amount" : "10" }, { "soNumber" : "52085848", "item" : "313330", "amount" : "5" }, { "soNumber" : "52085846", "item" : "313321", "amount" : "4" }, { "soNumber" : "52085843", "item" : "313338", "amount" : "13" }, { "soNumber" : "52085843", "item" : "422784", "amount" : "108" } ] // 整理soNumber成数组,并且从小到大排列 var soData = getSoData(arr); var newData = []; for ( var i in soData) { var midData = [] for ( var j in arr) { if (soData[i] == arr[j].soNumber) { midData.push(arr[j]); } } midData = midData.sort(function(obj1, obj2) { var val1 = Number(obj1.item); var val2 = Number(obj2.item); if (val1 < val2) { return -1; } else if (val1 > val2) { return 1; } else { return 0; } }); var itemData = [] for ( var m in midData) { if (itemData.indexOf(midData[m].item) == -1) { itemData.push(midData[m].item) } } for ( var n in itemData) { var midData1 = []; for ( var x in midData) { if (midData[x].item == itemData[n]) { midData1.push(midData[x]); } } midData1 = midData1.sort(function(obj1, obj2) { var val1 = Number(obj1.amount); var val2 = Number(obj2.amount); if (val1 < val2) { return -1; } else if (val1 > val2) { return 1; } else { return 0; } }); for ( var y in midData1) { newData.push(midData1[y]); } } } log.debug('newData', newData); return newData; } function getSoData(arr) { var soData = []; for ( var i in arr) { if (soData.indexOf(arr[i].soNumber) == -1) { soData.push(arr[i].soNumber); } } soData.sort(); log.debug('soData', soData); return soData; }

实现结果

从结果可以看出实现了依次按照soNumber ,item ,amount 从小到大排列

思考

从两层排序到三层排序我们可以发现代码原来越繁琐,如果要实现四层就更加麻烦了,不知道是否有更好的办法实现这种多维度,多层次的排序。

var arr = [ {"soNumber" : "52085848","item" : "313281","amount" : "3"}, {"soNumber" : "52085846","item" : "313321","amount" : "10"}, {"soNumber" : "52085848","item" : "313330","amount" : "5"}, {"soNumber" : "52085846","item" : "313321","amount" : "4"}, {"soNumber" : "52085843","item" : "313338","amount" : "13"}, {"soNumber" : "52085843","item" : "422784","amount" : "108"} ]

总结

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