解决方案

function mergeImgs(list) { const imgDom = document.createElement('img') document.body.appendChild(imgDom) const canvas = document.createElement('canvas') canvas.width = 500 canvas.height = 500 * list.length const context = canvas.getContext('2d') list.map((item, index) => { const img = new Image() img.src = item // 跨域 img.crossOrigin = 'Anonymous' img.onload = () => { context.drawImage(img, 0, 500 * index, 500, 500) const base64 = canvas.toDataURL('image/png') imgDom.setAttribute('src', base64) // console.log(baseList) } })}const urlList = ['./img/timg%20(1).jpg', './img/timg.jpg']mergeImgs(urlList )

代码稍微优化一下，改成公共方法

/** * 合并多张图片，返回新的图片 * @param {Array} list 图片url数组 * @param {Number} cwith 画布宽度 默认500 * @param {Number} cheight 画布高度 默认500 */function mergeImgs(list, cwith = 500, cheight = 500) { return new Promise((resolve, reject) => { const baseList = [] const canvas = document.createElement('canvas') canvas.width = cwith canvas.height = cheight * list.length const context = canvas.getContext('2d') list.map((item, index) => { const img = new Image() img.src = item // 跨域 img.crossOrigin = 'Anonymous' img.onload = () => { context.drawImage(img, 0, cheight * index, cwith, cheight) const base64 = canvas.toDataURL('image/png') baseList.push(base64) if (baseList[list.length - 1]) { console.log(baseList) // 返回新的图片 resolve(baseList[list.length - 1]) } } }) })}const urlList = ['./img/timg%20(1).jpg', './img/timg.jpg']mergeImgs(urlList ).then(base64 => { const imgDom = document.createElement('img') imgDom.src = base64 document.body.appendChild(imgDom)})

效果

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