本文实例讲述了ajax实现文件异步上传并回显文件相关信息功能。分享给大家供大家参考，具体如下：

上传文件的信息

<div class="form-group"> <div class="col-sm-4"> <label class="control-label">应用文件</label></div><div class="col-sm-8"> <input type="file" name="appFile" id="appFile"> <input type="submit" value="确认上传" id="subm"></div>

ajax提交

$("#subm").click(function(){ var formData = new FormData(); formData.append("appFile", document.getElementById("appFile").files[0]); alert("8888888888888888888888888"); $.ajax({ url: '${ctx}/appresources/fileUpload.shtml', type: "POST", data: formData, dataType: "json", contentType: false, processData: false, success: function (data) { alert("上传成功"); $("#versionCode").val(data.versionCode); $("#appVersion").val(data.appVersion); $("#appPackageName").val(data.appPackageName); }, error: function () { alert("上传失败！"); } });});

后台处理：

@ResponseBody@RequestMapping("fileUpload")public JSONObject fileUpload(MultipartFile appFile,Model model,HttpServletRequest request,HttpServletResponse response) { ServletContext//........................省略 String infos=ApkUtil.getApkInfo(needPath+"source"+File.separator+"apk"+File.separator+fileName); String[] info=infos.split(","); String versionCode=info[0];//版本号 String versionName=info[1];//版本名 String packageName=info[2];//包名 String appName=fileName; AppResourcesFormMap appResourcesFormMap = getFormMap(AppResourcesFormMap.class); appResourcesFormMap.put("appName",fileName); appResourcesFormMap.put("appVersion",versionName); appResourcesFormMap.put("appPackageName",packageName); appResourcesFormMap.put("versionCode", versionCode); System.out.println(appResourcesFormMap); //model.addAttribute("appresources", appResourcesFormMap); JSONObject fromObject = JSONObject.fromObject(appResourcesFormMap); //String string = fromObject.toString(); return fromObject;}

更多关于ajax相关内容感兴趣的读者可查看本站专题：《jquery中Ajax用法总结》、《JavaScript中ajax操作技巧总结》、《PHP+ajax技巧与应用小结》及《asp.net ajax技巧总结专题》

希望本文所述对大家ajax程序设计有所帮助。