Python实现批量下载文件

#!/usr/bin/env python# -*- coding:utf-8 -*-from gevent import monkeymonkey.patch_all()from gevent.pool import Poolimport requestsimport sysimport osdef download(url): chrome = 'Mozilla/5.0 (X11; Linux i86_64) AppleWebKit/537.36 ' + '(KHTML, like Gecko) Chrome/41.0.2272.101 Safari/537.36' headers = {'User-Agent': chrome} filename = url.split('/')[-1].strip() r = requests.get(url.strip(), headers=headers, stream=True) with open(filename, 'wb') as f: for chunk in r.iter_content(chunk_size=1024): if chunk:f.write(chunk)f.flush() print filename,"is ok"def removeLine(key, filename): os.system('sed -i /%s/d %s' % (key, filename))if __name__ =="__main__": if len(sys.argv) == 2: filename = sys.argv[1] f = open(filename,"r") p = Pool(4) for line in f.readlines(): if line: p.spawn(download, line.strip()) key = line.split('/')[-1].strip() removeLine(key, filename)f.close()p.join()else: print 'Usage: python %s urls.txt' % sys.argv[0]

其他网友的方法：

from os.path import basenamefrom urlparse import urlsplitdef url2name(url): return basename(urlsplit(url)[2])def download(url, localFileName = None): localName = url2name(url) req = urllib2.Request(url) r = urllib2.urlopen(req) if r.info().has_key('Content-Disposition'): # If the response has Content-Disposition, we take file name from it localName = r.info()['Content-Disposition'].split('filename=')[1] if localName[0] == '"' or localName[0] == "'": localName = localName[1:-1] elif r.url != url: # if we were redirected, the real file name we take from the final URL localName = url2name(r.url) if localFileName: # we can force to save the file as specified name localName = localFileName f = open(localName, 'wb') f.write(r.read()) f.close()download(r'你要下载的python文件的url地址')

以上便是本文给大家分享的全部内容了，小伙伴们可以测试下哪种方法效率更高呢。