SQL Server中将查询结果转换为Json格式脚本分享

时间:2021-05-23

脚本源码:

复制代码 代码如下:
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE PROCEDURE[dbo].[SerializeJSON](
@ParameterSQL AS VARCHAR(MAX)
)
AS
BEGIN
DECLARE @SQL NVARCHAR(MAX)
DECLARE @XMLString VARCHAR(MAX)
DECLARE @XML XML
DECLARE @Paramlist NVARCHAR(1000)
SET @Paramlist = N'@XML XML OUTPUT'
SET @SQL = 'WITH PrepareTable (XMLString)'
SET @SQL = @SQL + 'AS('
SET @SQL = @SQL + @ParameterSQL+ 'FOR XML RAW,TYPE,ELEMENTS'
SET @SQL = @SQL + ')'
SET @SQL = @SQL + 'SELECT @XML=[XMLString]FROM[PrepareTable]'
EXEC sp_executesql @SQL, @Paramlist, @XML=@XML OUTPUT
SET @XMLString=CAST(@XML AS VARCHAR(MAX))
DECLARE @JSON VARCHAR(MAX)
DECLARE @Row VARCHAR(MAX)
DECLARE @RowStart INT
DECLARE @RowEnd INT
DECLARE @FieldStart INT
DECLARE @FieldEnd INT
DECLARE @KEY VARCHAR(MAX)
DECLARE @Value VARCHAR(MAX)
DECLARE @StartRoot VARCHAR(100);SET @StartRoot='<row>'
DECLARE @EndRoot VARCHAR(100);SET @EndRoot='</row>'
DECLARE @StartField VARCHAR(100);SET @StartField='<'
DECLARE @EndField VARCHAR(100);SET @EndField='>'
SET @RowStart=CharIndex(@StartRoot,@XMLString,0)
SET @JSON=''
WHILE @RowStart>0
BEGIN
SET @RowStart=@RowStart+Len(@StartRoot)
SET @RowEnd=CharIndex(@EndRoot,@XMLString,@RowStart)
SET @Row=SubString(@XMLString,@RowStart,@RowEnd-@RowStart)
SET @JSON=@JSON+'{'
-- for each row
SET @FieldStart=CharIndex(@StartField,@Row,0)
WHILE @FieldStart>0
BEGIN
-- parse node key
SET @FieldStart=@FieldStart+Len(@StartField)
SET @FieldEnd=CharIndex(@EndField,@Row,@FieldStart)
SET @KEY=SubString(@Row,@FieldStart,@FieldEnd-@FieldStart)
SET @JSON=@JSON+'"'+@KEY+'":'
-- parse node value
SET @FieldStart=@FieldEnd+1
SET @FieldEnd=CharIndex('</',@Row,@FieldStart)
SET @Value=SubString(@Row,@FieldStart,@FieldEnd-@FieldStart)
SET @JSON=@JSON+'"'+@Value+'",'
SET @FieldStart=@FieldStart+Len(@StartField)
SET @FieldEnd=CharIndex(@EndField,@Row,@FieldStart)
SET @FieldStart=CharIndex(@StartField,@Row,@FieldEnd)
END
IF LEN(@JSON)>0SET @JSON=SubString(@JSON,0,LEN(@JSON))
SET @JSON=@JSON+'},'
--/ for each row
SET @RowStart=CharIndex(@StartRoot,@XMLString,@RowEnd)
END
IF LEN(@JSON)>0SET @JSON=SubString(@JSON,0,LEN(@JSON))
SET @JSON='['+@JSON+']'
SELECT @JSON
END
GO

使用方法:
复制代码 代码如下:
EXEC[SerializeJSON]'SELECT*FROM[Employee_TBL]'

声明:本页内容来源网络,仅供用户参考;我单位不保证亦不表示资料全面及准确无误,也不保证亦不表示这些资料为最新信息,如因任何原因,本网内容或者用户因倚赖本网内容造成任何损失或损害,我单位将不会负任何法律责任。如涉及版权问题,请提交至online#300.cn邮箱联系删除。

相关文章