时间:2021-05-19
本文实例为大家分享了基于easyx的C++实现贪吃蛇的具体代码,供大家参考,具体内容如下
本代码来自于easyx讨论群的分享
先上效果图,其实也只是画了简单的圈圈代表蛇和食物,背景就是黑色的。
#include "stdafx.h"#include <iostream>#include <stdlib.h>#include <time.h>#include <conio.h>#include <graphics.h> #define N 100 using namespace std; enum moved { UP, DOWN, LEFT, RIGHT };class Snake {private: struct { //整条蛇的信息 int x; int y; }snake[100]; struct { int life; //为1代表还活着,为0代表已经死了 int length; //代表蛇的长度,初始值为3 enum moved direction; //前进方向 }snake_head; struct { //食物的信息 int x; int y; }food;public: void display(); //显示界面 void initSnake(); //随机生成蛇 void move();//蛇移动 void boundary_check();//边界判断 void _food();//生成食物 int food_eatcheck();//检查是否吃到食物,吃到则返回1,否则返回0 int snake_eat();//判断贪吃蛇是否咬到自己,咬到则返回1,否则返回0 void run(); //主要运行函数};void Snake::display() { initgraph(800, 600); setbkcolor(WHITE); //设置背景颜色为白色 cleardevice(); //将背景颜色刷新到窗口上 setfillcolor(BLACK); //设置填充的颜色为黑色,之后话填充的图形都是这个颜色 solidrectangle(20, 560, 560, 20);//这个区域每20*20为一个单位,一共有27*27个单位}//构造函数void Snake::initSnake() { srand((unsigned)time(NULL)); //因为一开始蛇是向右走的,所以不能让蛇初始化在太靠右边的地方 int x = rand() % 22 + 3; //范围是3-24 int y = rand() % 22 + 3; //加三是因为初始的长度是3,必须让整条蛇都在范围内 this->snake[0].x = x * 20 + 10;//加十是因为要确定圆心的位置 this->snake[0].y = y * 20 + 10; //默认蛇一开始是横着的所以三段的y坐标相同 this->snake[1].y = this->snake[2].y = this->snake[0].y; this->snake[1].x = this->snake[0].x - 20; this->snake[2].x = this->snake[0].x - 40; setfillcolor(GREEN); //设置填充色为绿色 solidcircle(this->snake[0].x, this->snake[0].y, 10); //画圆 solidcircle(this->snake[1].x, this->snake[1].y, 10); solidcircle(this->snake[2].x, this->snake[2].y, 10); this->snake_head.length = 3; this->snake_head.life = 1; this->snake_head.direction = RIGHT;}void Snake::move() { char ch; if (_kbhit()) { //如果有输入的话就返回1,没有输入的话就返回0 ch = _getch();//获取输入的字符 switch (ch) { case 'w' :if (this->snake_head.direction != DOWN) this->snake_head.direction = UP; break; case 'W':if (this->snake_head.direction != DOWN) this->snake_head.direction = UP; break; case 's' :if (this->snake_head.direction != UP) this->snake_head.direction = DOWN; break; case 'S':if (this->snake_head.direction != UP) this->snake_head.direction = DOWN; break; case 'a':if (this->snake_head.direction != RIGHT) this->snake_head.direction = LEFT; break; case 'A':if (this->snake_head.direction != RIGHT) this->snake_head.direction = LEFT; break; case 'd':if (this->snake_head.direction != LEFT) this->snake_head.direction = RIGHT; break; case 'D':if (this->snake_head.direction != LEFT) this->snake_head.direction = RIGHT; break; default:break; } } //将蛇尾变成黑色 int i = this->snake_head.length - 1; setfillcolor(BLACK); solidcircle(snake[i].x, snake[i].y, 10); //接下来遍历每个身体,每个身体都更新为前一个身体,蛇头除外 for (; i > 0; i--) { this->snake[i].x = this->snake[i - 1].x; this->snake[i].y = this->snake[i - 1].y; } switch (this->snake_head.direction) { case RIGHT:this->snake[0].x += 20; break; case LEFT:this->snake[0].x -= 20; break; case UP:this->snake[0].y -= 20; break; case DOWN:this->snake[0].y += 20; break; default:break; } setfillcolor(GREEN); solidcircle(this->snake[0].x, this->snake[0].y, 10);//绘制蛇头 Sleep(1000);}void Snake::boundary_check() { if (this->snake[0].x <= 30 || this->snake[0].x >= 550 || this->snake[0].y <= 30 || this->snake[0].y >= 550) { this->snake_head.life = 0; }}void Snake::_food() { srand((unsigned)time(NULL)); int x = rand() % 21 + 3; //范围是3-23 int y = rand() % 21 + 3; this->food.x = x * 20 + 10; this->food.y = y * 20 + 10; setfillcolor(YELLOW); solidcircle(this->food.x, this->food.y, 10);}int Snake::food_eatcheck() { if (this->snake[0].x == this->food.x && this->snake[0].y == this->food.y) { //如果满足条件就是吃到食物了 this->snake_head.length++;//长度加一 setfillcolor(GREEN); solidcircle(food.x, food.y, 10); int k = this->snake_head.length; //吃到食物之后最后要在尾巴处加一个长度 switch (this->snake_head.direction) { case RIGHT:this->snake[k - 1].x = this->snake[k - 2].x - 20; this->snake[k - 1].y = this->snake[k - 2].y; break; case LEFT:this->snake[k - 1].x = this->snake[k - 2].x += 20; this->snake[k - 1].y = this->snake[k - 2].y; break; case UP:this->snake[k - 1].x = this->snake[k - 2].x; this->snake[k - 1].y = this->snake[k - 2].y + 20; break; case DOWN:this->snake[k - 1].x = this->snake[k - 2].x; this->snake[k - 1].y = this->snake[k - 2].y - 20; break; default:break; } setfillcolor(GREEN); solidcircle(this->snake[k - 1].x, this->snake[k - 1].y, 10); return 1; } return 0;}int Snake::snake_eat() { int i; for (i = 1; i < this->snake_head.length; i++) { if (this->snake[i].x == this->snake[0].x && this->snake[i].y == this->snake[0].y) { return 1; } } return 0;}void Snake::run() { display(); //显示游戏界面 initSnake(); _food(); //生成第一个食物 while (true) { move(); //蛇移动 if (snake_eat() == 1) { //自己吃到自己了,游戏失败 cout << "自己吃到自己了,游戏失败" << endl; break; } boundary_check();//判断是否撞墙 if (this->snake_head.life == 0) { //撞墙了 cout << "撞墙了,游戏结束" << endl; break; } if (food_eatcheck() == 1) { _food(); //吃到食物就重新生成一个食物 } }} int main() { Snake s; s.run(); return 0;}更多有趣的经典小游戏实现专题,分享给大家:
C++经典小游戏汇总
python经典小游戏汇总
python俄罗斯方块游戏集合
JavaScript经典游戏 玩不停
javascript经典小游戏汇总
以上就是本文的全部内容,希望对大家的学习有所帮助,也希望大家多多支持。
声明:本页内容来源网络,仅供用户参考;我单位不保证亦不表示资料全面及准确无误,也不保证亦不表示这些资料为最新信息,如因任何原因,本网内容或者用户因倚赖本网内容造成任何损失或损害,我单位将不会负任何法律责任。如涉及版权问题,请提交至online#300.cn邮箱联系删除。
我大概在一个多月前把自己上学期写的c代码的贪吃蛇游戏push到csdn上,并且说c风格的贪吃蛇写起来有些麻烦(贪吃蛇游戏的c语言实现),准备用面向对象的c++再
本文实例为大家分享了C++实现贪吃蛇游戏的具体代码,供大家参考,具体内容如下刚学完了C语言,便尝试的写了贪吃蛇的代码,但是效果不佳,很多的bug,所以,这个学了
本文实例讲述了贪吃蛇游戏C++命令行版的实现代码,是非常经典的游戏。分享给大家供大家参考。具体实现方法如下:众所周知,贪吃蛇游戏是经典的计算机游戏。游戏描述如下
本文以实例的形式讲述了基于C语言实现的贪吃蛇游戏代码,这是一个比较常见的游戏,代码备有比较详细的注释,对于读者理解有一定的帮助。贪吃蛇完整实现代码如下:#inc
本文实例为大家分享了C语言实现贪吃蛇的具体代码,供大家参考,具体内容如下用C语言链表写的贪吃蛇(程序设计时做的,做的不好大佬勿喷)借助游戏内容分析贪吃蛇所需的功