最近整理下电脑，看到了自己在上个学期打的贪吃蛇游戏的c代码，觉得真的是略微有点冗长，但是实现起来应该也算是比较好理解，于是把自己的代码搬上来，网络上写贪吃蛇的c语言的文章很多，我这篇也仅是给大家作为一个参考而已。

我的代码是在Windows下运行的，因为需要用到windows.h这个库。

然后也做了一个简单的ai模式，这在没有障碍物的情况下前期还是蛮不错的，但是到了后期蛇变长了之后就会有bug了。
好了，直接上代码吧：

1）头文件和宏定义

#include<stdio.h>#include<stdlib.h>#include<time.h>#include<conio.h>#include<windows.h>#define SNAKE_MAX_LENGTH 20#define SNAKE_HEAD 'H'#define SNAKE_BODY 'X'#define BLANK_CELL ''#define SNAKE_FOOD '$'#define WALL_CELL '*'

2）各种实现函数的声明

void snakemove(int, int); //to write dowm the current location of the snake void put_money(void); void output(void); // to put the current map on the screenvoid initial_the_game(void);void put_accelerate(void);// @ is a special food which can speed up your snake.int judge(int, int); int dis(int, int); // when it coomes to ai, it is used to calculate the current distence //between the snake head and the food.void welcome(void); // the game introduction.void gameover(void); void edition_handed(void); // the edition in which you can play by yourself.void edition_presentation(void); // the edition in which the snake can go automatically.

3）各种全局变量

// define vars for snake,notice name of vars in c int snakeX[SNAKE_MAX_LENGTH] = {1, 2, 3, 4, 5};int snakeY[SNAKE_MAX_LENGTH] = {1, 1, 1, 1, 1};int snakeLength = 5;int gamestate = 1;int current_speed = 600;int score = 0;char edition_choose; // for player to choose the edition.int con = 1; // to judge the initial state of the game;int energy = 0; // write down the condition to accelerate by eating $.//the following part is to realize the simple ai .const char movable[4] = {'a', 'd', 's', 'w'};int distance[4] = {9999, 9999, 9999, 9999};int fx = 6, fy = 6; // the coordinate of the food $

4）地图

char map[12][12] = {"************", "*XXXXH *", "* *", "* *", "* *", "* *", "* $ *", "* *", "* @ *", "* *", "* *", "************"};

5）主函数（可选模式）

int main() { while (con) { welcome(); int flag = 1; while (flag) { edition_choose = getch(); //choose the edition if (edition_choose == 'h') { edition_handed(); flag = 0; } else if (edition_choose == 'p') { edition_presentation(); flag = 0; } else { printf("Please press the correct bottom -,- ...\n"); } } gameover(); } return 0;}

6）手动模式实现

void edition_handed(void) { system("cls"); output(); char ch = 'd'; while (gamestate) { switch (ch) { case 'a': // go left while (1) { snakemove(-1, 0); Sleep(current_speed); if (gamestate == 0) // to break the loop if the snake hit the wall or itself. break; if (kbhit() != 0) { // to change the direction ch = getch(); if (ch == 's' || ch == 'w') break; else ch = 'a'; } } break; case 'd': // go right while (1) { snakemove(1, 0); Sleep(current_speed); if (gamestate == 0) break; if (kbhit() != 0) ch = getch(); if (ch == 's' || ch == 'w') break; else ch = 'd'; } break; case 's': // go down while (1) { snakemove(0, 1); Sleep(current_speed); if (gamestate == 0) break; if (kbhit() != 0) ch = getch(); if (ch == 'a' || ch == 'd') break; else ch = 's'; } break; case 'w': // go up while (1) { snakemove(0, -1); Sleep(current_speed); if (gamestate == 0) break; if (kbhit() != 0) ch = getch(); if (ch == 'a' || ch == 'd') break; else ch = 'w'; } break; } if (gamestate == 0) break; } return;}

7）自动模式实现

void edition_presentation(void) { // for ai system("cls"); int i, min = 10000; output(); char ch; char quit = 'o'; int k; while (gamestate) { // find the shortest way; min = 10000; if (judge(-1, 0)) distance[0] = dis(-1, 0); if (judge(1, 0)) distance[1] = dis(1, 0); if (judge(0, 1)) distance[2] = dis(0, 1); if (judge(0, -1)) distance[3] = dis(0, -1); for (i = 0; i < 4; i++) { if (min >= distance[i]) { min = distance[i]; k = i; } } Sleep(current_speed); switch (movable[k]) { case 'a': // go left snakemove(-1, 0); break; case 'd': // go right snakemove(1, 0); break; case 's': // go down snakemove(0, 1); break; case 'w': // go up snakemove(0, -1); break; } if (gamestate == 0) break; system("cls"); output(); } return;}

8）其他辅助函数

欢迎界面

void welcome(void) { // just for some introduction printf("WELCOME TO THE SNAKE'S WORLD !!!!\n"); printf("\n"); printf("\n"); printf("Please choose the edition you want.\n"); printf("\n"); printf("\n"); printf("The 'h' is for the hand-operated and the 'p' is for the simple presentation\n"); printf("\n"); printf("\n"); printf("Attention: the presentation still has a liitle bug, while it can be moving right for a period of time...\n "); return;}

游戏结束界面

void gameover(void) { // give you some introduction when you lose the game. system("cls"); printf("Game over!!!\n"); printf("Do you want to continue? y or n\n"); char start; // in order to judge whether you still want to play the game. while (1) { start = getch(); if (start == 'y') { system("cls"); initial_the_game(); break; } else if (start == 'n') { system("cls"); con = 0; // in order to let the game end. printf("See you next time! ^-^\n"); break; } else { printf("Please press the correct buttom.\n"); } }}

图像实现方式

void output(void) { // put the cuttent game map. printf("THE INTERESTING SNAKE GAME CREATED BY LONGJ =,=\n"); printf("use w~s~a~d to control the snake's movement\n"); printf("ATTENTION: the @ can speed up your lovely snake~~\n"); int i, j; for (i = 0; i < 12; i++) { for (j = 0; j < 12; j++) { printf("%c", map[i][j]); if (j == 11) printf("\n"); } } printf("Your current_speed is %d\n", current_speed); printf("The number of your food undigested is %d (when it comes to 5, your speed will be accelerated!) \n", energy); printf("SCORE = %d\n", score); return;}

蛇的行走实现

void snakemove(int dx, int dy) { // all the conditions are comparing the head and the next position. int i; if (snakeY[snakeLength - 1] + dy == snakeY[snakeLength - 2] && snakeX[snakeLength - 1] + dx == snakeX[snakeLength - 2]) return; // to prevent it go to itslef. if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == 'X') { gamestate = 0; return; } if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == '*') { gamestate = 0; return; } if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == ' ' || map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == '@') { map[snakeY[0]][snakeX[0]] = ' '; // clear the former_tail if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == '@' && current_speed > 100) { // what will happen when your snake eats the @ current_speed -= 100; put_accelerate(); } for (i = 0; i < snakeLength - 1; ++i) { snakeX[i] = snakeX[i + 1]; snakeY[i] = snakeY[i + 1]; } snakeX[snakeLength - 1] += dx; snakeY[snakeLength - 1] += dy; for (i = 0; i < snakeLength - 1; i++) // write down the current snake location map[snakeY[i]][snakeX[i]] = 'X'; map[snakeY[snakeLength - 1]][snakeX[snakeLength - 1]] = 'H'; } if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == '$') { map[snakeY[snakeLength - 1]][snakeX[snakeLength - 1]] = 'X'; snakeLength++; snakeX[snakeLength - 1] = snakeX[snakeLength - 2] + dx; snakeY[snakeLength - 1] = snakeY[snakeLength - 2] + dy; map[snakeY[snakeLength - 1]][snakeX[snakeLength - 1]] = 'H'; score++; energy++; if (energy == 5 && current_speed > 50) { current_speed -= 50; energy = 0; } put_money(); } system("cls"); output(); return;}

食物放置的实现

void put_money(void) { /// ai will change the code int flag = 1; while (flag) { srand(time(NULL)); fx = rand() % 12; fy = rand() % 12; if (map[fy][fx] == ' ') { map[fy][fx] = '$'; flag = 0; } if (edition_choose == 'p') { int i; for (i = 0; i< 4; i++) distance[i] = 9999; } } return;}void put_accelerate(void) { int x, y, flag = 1; while (flag) { srand(time(NULL)); x = rand() % 12; y = rand() % 12; if (map[x][y] == ' ') { map[x][y] = '@'; flag = 0; } } return;}

ai辅助函数

int dis(int dx, int dy) { return abs(fx - snakeX[snakeLength - 1] - dx) + abs(fy - snakeY[snakeLength - 1] - dy);}int judge(int dx, int dy) { if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == ' ') return 1; else if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == '$') return 1; else if (map[snakeY[snakeLength - 1] + dy][snakeX[snakeLength - 1] + dx] == '@') return 1; else return 0;}

游戏over后的初始化函数：

void initial_the_game(void) { int i, j, count = 1; snakeLength = 5; gamestate = 1; fx = fy = 6; current_speed = 600; for (i = 0; i < 5; i++) snakeY[i] = 1; for (i = 0; i < 5; i++) { snakeX[i] = count++; } for (j = 0; j < 12; j++) { map[0][j] = '*'; map[11][j] = '*'; } for (i = 1; i < 11; i++) { map[i][0] = map[i][11] = '*'; for (j = 1; j < 11; j++) map[i][j] = ' '; } map[fy][fx] ='$'; map[8][4] = '@'; for (i = 0; i< 4; i++) { distance[i] = 9999; } for (i = 0; i < 4; i++) map[snakeY[i]][snakeX[i]] = 'X'; map[snakeY[4]][snakeX[4]] = 'H'; return;}

小结：

不难看出，c语言代码比较冗长，而且初始化的函数实现起来十分麻烦，稍有不慎就会全部出错，导致游戏无法持续玩下去，博主当初写的时候就是被坑了很久=_=

因而现在在学c++，希望以后把类的概念之类的东西都弄得更加熟练之后，可以去把这个冗长的c代码改成更加简洁，阅读性更强的c++代码。

（好的，已经更新了，写出了一个比较简单的C++贪吃蛇，的确是思路清晰很多，代码的可读性更高。）

这篇博客给那些想要用c来写贪吃蛇的同学一些参考，运行起来是没有问题的，可以选择性看：）

以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持。